-16x^2=28x+10

Solution for -16x^2=28x+10 equation:

-16x^2=28x+10

We move all terms to the left:

-16x^2-(28x+10)=0

We get rid of parentheses

-16x^2-28x-10=0

a = -16; b = -28; c = -10;
Δ = b2-4ac
Δ = -282-4·(-16)·(-10)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-12}{2*-16}=\frac{16}{-32}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+12}{2*-16}=\frac{40}{-32}
=-1+1/4
$